4v^2=-28+32v

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Solution for 4v^2=-28+32v equation:


Simplifying
4v2 = -28 + 32v

Solving
4v2 = -28 + 32v

Solving for variable 'v'.

Reorder the terms:
28 + -32v + 4v2 = -28 + 32v + 28 + -32v

Reorder the terms:
28 + -32v + 4v2 = -28 + 28 + 32v + -32v

Combine like terms: -28 + 28 = 0
28 + -32v + 4v2 = 0 + 32v + -32v
28 + -32v + 4v2 = 32v + -32v

Combine like terms: 32v + -32v = 0
28 + -32v + 4v2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(7 + -8v + v2) = 0

Factor a trinomial.
4((1 + -1v)(7 + -1v)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(1 + -1v)' equal to zero and attempt to solve: Simplifying 1 + -1v = 0 Solving 1 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1v = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1v = 0 + -1 -1v = 0 + -1 Combine like terms: 0 + -1 = -1 -1v = -1 Divide each side by '-1'. v = 1 Simplifying v = 1

Subproblem 2

Set the factor '(7 + -1v)' equal to zero and attempt to solve: Simplifying 7 + -1v = 0 Solving 7 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1v = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1v = 0 + -7 -1v = 0 + -7 Combine like terms: 0 + -7 = -7 -1v = -7 Divide each side by '-1'. v = 7 Simplifying v = 7

Solution

v = {1, 7}

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